x^2+0.46x-0.12=0

Solution for x^2+0.46x-0.12=0 equation:

x^2+0.46x-0.12=0

a = 1; b = 0.46; c = -0.12;
Δ = b2-4ac
Δ = 0.462-4·1·(-0.12)
Δ = 0.6916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.46)-\sqrt{0.6916}}{2*1}=\frac{-0.46-\sqrt{0.6916}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.46)+\sqrt{0.6916}}{2*1}=\frac{-0.46+\sqrt{0.6916}}{2}
$